document.write( "Question 62570: I need your help thank U:\r
\n" ); document.write( "\n" ); document.write( "sqrt 5x-2 +8=0\r
\n" ); document.write( "\n" ); document.write( "5x-2 under the radical(Square root)
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Algebra.Com's Answer #43333 by funmath(2933)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%285x-2%29%2B8=0\"
\n" ); document.write( "\"sqrt%285x-2%29%2B8-8=0-8\"
\n" ); document.write( "\"sqrt%285x-2%29=-8\"
\n" ); document.write( "\"%28sqrt%285x-2%29%29%5E2=%28-8%29%5E2\"
\n" ); document.write( "\"5x-2=64\"
\n" ); document.write( "\"5x-2%2B2=64%2B2\"
\n" ); document.write( "\"5x=66\"
\n" ); document.write( "\"5x%2F5=66%2F5\"
\n" ); document.write( "\"x=66%2F5\"
\n" ); document.write( "Check for extraneous solutions.
\n" ); document.write( "\"sqrt%285%2866%2F5%29-2%29%2B8=0\"
\n" ); document.write( "\"sqrt%2866-2%29%2B8=0\"
\n" ); document.write( "\"sqrt%2864%29%2B8=0\"
\n" ); document.write( "\"8%2B8=0\"
\n" ); document.write( "\"16=0\" x=66/5 is extraneous, this has no solution.
\n" ); document.write( "Happy Calculating!!!
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