document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=703023>Question 703023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you solve this linear system by using substitution?\r<BR>\n" );
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document.write( "0.5x+y=9<BR>\n" );
document.write( "1.6x+0.2y=13<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433268 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433268\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.5x+y=9<BR>\n" );
document.write( "1.6x+0.2y=13<BR>\n" );
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document.write( "y = 9-0.5x<BR>\n" );
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document.write( "Substitute for \"y\" and solve for \"x\":<BR>\n" );
document.write( "1.6x + 0.2(9-0.5x) = 13<BR>\n" );
document.write( "1.6x + 1.8 -0.01x = 13<BR>\n" );
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document.write( "1.59x = 11.2<BR>\n" );
document.write( "x = 7.044<BR>\n" );
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document.write( "Solve for \"y\":<BR>\n" );
document.write( "y = 9-0.5(7.044)<BR>\n" );
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document.write( "y = 5.48<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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