document.write( "Question 703007: 1/x² - 1/y² over 1/xy² - 1/x²y² \n" ); document.write( "
Algebra.Com's Answer #433267 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1/x² - 1/y² over 1/xy² - 1/x²y²
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\n" ); document.write( "(x^2-y^2)/(x^2y^2) over (x^2y^2-xy^2)/(x^3y^4)
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\n" ); document.write( "(x^2-y^2)/(x^2y^2) over (xy^2(x-1)/(x^3y^4)
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\n" ); document.write( "Invert the denominator and multiply:
\n" ); document.write( "(x^2-y^2)/(x^2y^2) times (x^3y^4)/(xy^2(x-1))
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\n" ); document.write( "[(x^2-y^2)/(xy^2(x-1)] * [xy^2/1]
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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