document.write( "Question 703007: 1/x² - 1/y² over 1/xy² - 1/x²y² \n" ); document.write( "
Algebra.Com's Answer #433267 by stanbon(75887) ![]() You can put this solution on YOUR website! 1/x² - 1/y² over 1/xy² - 1/x²y² \n" ); document.write( "----------------------------------------- \n" ); document.write( "(x^2-y^2)/(x^2y^2) over (x^2y^2-xy^2)/(x^3y^4) \n" ); document.write( "----------------------------------------- \n" ); document.write( "(x^2-y^2)/(x^2y^2) over (xy^2(x-1)/(x^3y^4) \n" ); document.write( "---------------------- \n" ); document.write( "Invert the denominator and multiply: \n" ); document.write( "(x^2-y^2)/(x^2y^2) times (x^3y^4)/(xy^2(x-1)) \n" ); document.write( "--------- \n" ); document.write( "[(x^2-y^2)/(xy^2(x-1)] * [xy^2/1] \n" ); document.write( "-------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=====================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |