document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=702980>Question 702980</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A beverage company mixes a beverage that contains 10% fruit juice with another one that contains 50% fruit juice. How many gallons of each should they mix to obtain 1300 gallons of a mix that contains 40% fruit juice ?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433259 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .50x+.10(1300-x)=.40*1300<BR>\n" );
document.write( ".50x+130-.10x=520<BR>\n" );
document.write( ".40x=520-130<BR>\n" );
document.write( ".40x=390<BR>\n" );
document.write( "x=390/.40<BR>\n" );
document.write( "x=975 gal. of 50% juice is used.<BR>\n" );
document.write( "1300-975=325 gal of 10% juice is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".50*975+.10*325=.40*1300<BR>\n" );
document.write( "487.5+32.5=520<BR>\n" );
document.write( "520=520<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );