document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=702873>Question 702873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle is three times as long as it is wide. The perimeter is 144 feet. Find the dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433224 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433224\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x is length.  w is width.\r<BR>\n" );
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document.write( "Three times as long as it is wide:  x=3w\r<BR>\n" );
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document.write( "Perimeter is 144:  144=2x+2w\r<BR>\n" );
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document.write( "Easiest way is substitute x from first equation into the second equation.<BR>\n" );
document.write( "144=2(3w)+2w<BR>\n" );
document.write( "144=8w<BR>\n" );
document.write( "w=144/8=72/4=36/2=18.\r<BR>\n" );
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document.write( "w=18 means x=3(18)=36 </SPAN>\n" );
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