document.write( "Question 702805: What is the center of the circle given by the equation below?
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document.write( "x2 - 16x + y2 - 18y = -129 \n" );
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Algebra.Com's Answer #433170 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! What is the center of the circle given by the equation below? \n" ); document.write( "x2 - 16x + y2 - 18y = -129 \n" ); document.write( "---- \n" ); document.write( "Complete the square on the x and on the y terms: \n" ); document.write( "x^2 -16x + 64 + y^2 -18y + 81 = -129+64+81 \n" ); document.write( "----- \n" ); document.write( "Factor: \n" ); document.write( "(x-8)^2 + (y-9)^2 = 16 \n" ); document.write( "---- \n" ); document.write( "Center: (8,9) \n" ); document.write( "radius: sqrt(16) = 4 \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "======================== \n" ); document.write( " |