document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=702772>Question 702772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A church building fund has invested money in two ways:part of the money at 3% interest and 4 times as much as 2.75%.Find the amount invested at each rate if the total annual income from interest is $2,800 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433132 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let church invested x at 3% & 4x at 2.75% & the total interest is 2800<BR>\n" );
document.write( "so 3x/100+2.75*4x/100=2800<BR>\n" );
document.write( "or 3x+11x=2800*100=280000<BR>\n" );
document.write( "or 14x=280000<BR>\n" );
document.write( "or x=20000<BR>\n" );
document.write( "so the amount invested 20000 at 3% & 800000 at 2.75%<BR>\n" );
document.write( "ans </SPAN>\n" );
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