document.write( "Question 7870: 3x+17>5 \n" ); document.write( "

Algebra.Com's Answer #4331 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"3x+%2B+17+%3E+5\"$ Subtract 17 from both sides.\r
\n" ); document.write( "\n" ); document.write( " $\"3x+%3E+-12\"$ Divide both sides by 3.\r
\n" ); document.write( "\n" ); document.write( " $\"x+%3E+-4\"$ \r
\n" ); document.write( "\n" ); document.write( "Check: \r
\n" ); document.write( "\n" ); document.write( "Choose a value of x that is greater than -4, let's say -2.\r
\n" ); document.write( "\n" ); document.write( " $\"3%28-2%29+%2B+17+%3E+5\"$
\n" ); document.write( " $\"-6+%2B+17+%3E+5\"$
\n" ); document.write( " $\"11+%3E+5\"$ Check is ok. \n" ); document.write( "

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