document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=702675>Question 702675</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains are 600 miles apart, and their speeds differ by 20miles per hour. Find the speed of each train if they are traveling towards each other and will meet in three hours?  I know the answers are 90 and 110, I just can't figure out the equation or how to get the answer. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+please+help ALIGN=MIDDLE  ALT=\"+please+help\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "          R.   T. =  D<BR>\n" );
document.write( "     A- x. .  3 = 3x<BR>\n" );
document.write( "                                             <BR>\n" );
document.write( "     B.(x-20).  3 = 3(-20)<BR>\n" );
document.write( "                         D = 600\r<BR>\n" );
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document.write( "I can't figure out what I'm doing wrong? I'm having a hard time with this chapter on how to set the problems up. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433092 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two trains are 600 miles apart, and their speeds differ by 20miles per hour. Find the speed of each train if they are traveling towards each other and will meet in three hours? I know the answers are 90 and 110, I just can't figure out the equation or how to get the answer. <BR>\n" );
document.write( "Let x = speed of slower train<BR>\n" );
document.write( "then<BR>\n" );
document.write( "x+20 = speed of faster train<BR>\n" );
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document.write( "3(x + x+20) = 600<BR>\n" );
document.write( "x + x+20 = 200<BR>\n" );
document.write( "2x+20 = 200<BR>\n" );
document.write( "2x = 180<BR>\n" );
document.write( "x = 90 mph (slower train)<BR>\n" );
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document.write( "Faster train:<BR>\n" );
document.write( "x+20 = 90+20 = 110 mph\r<BR>\n" );
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