document.write( "Question 48799: Solve the following:\r
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document.write( "80 = 10x\r
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document.write( "Solve:\r
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document.write( "2/5x = -10 \n" );
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Algebra.Com's Answer #43307 by mystic1306(20)![]() ![]() You can put this solution on YOUR website! 80=10x \n" ); document.write( "First get the x by itself \n" ); document.write( "to do this divide both sides by 10 \n" ); document.write( "80/10=8 \n" ); document.write( "10x/10= 1x or x\r \n" ); document.write( "\n" ); document.write( "so.. \n" ); document.write( "8=x \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2/5x= -10 \n" ); document.write( "get the x by itself by multiplying both sides by 5 to make the 5 a fraction put 5 over 1 \n" ); document.write( " \n" ); document.write( "2x/5 times 5/1 the fives cancel so you have 2x/1 or 2x \r \n" ); document.write( "\n" ); document.write( "-10 times 5= -50 \n" ); document.write( "so \n" ); document.write( "2x= -50 \n" ); document.write( "now divide both sides by 2 \n" ); document.write( "2x/2=1x or x \n" ); document.write( "-50/2= -25 \n" ); document.write( "x=-25\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "just to show you: \n" ); document.write( "2x/5 times 5/1= 2x \n" ); document.write( "-10 times 5= -50\r \n" ); document.write( "\n" ); document.write( "2x= -50\r \n" ); document.write( "\n" ); document.write( "2x/2=x \n" ); document.write( "-50/2= -25\r \n" ); document.write( "\n" ); document.write( "x= -25 \n" ); document.write( " |