document.write( "Question 48799: Solve the following:\r
\n" ); document.write( "\n" ); document.write( "80 = 10x\r
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\n" ); document.write( "\n" ); document.write( "Solve:\r
\n" ); document.write( "\n" ); document.write( "2/5x = -10
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Algebra.Com's Answer #43307 by mystic1306(20)\"\" \"About 
You can put this solution on YOUR website!
80=10x
\n" ); document.write( "First get the x by itself
\n" ); document.write( "to do this divide both sides by 10
\n" ); document.write( "80/10=8
\n" ); document.write( "10x/10= 1x or x\r
\n" ); document.write( "\n" ); document.write( "so..
\n" ); document.write( "8=x \r
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\n" ); document.write( "\n" ); document.write( "2/5x= -10
\n" ); document.write( "get the x by itself by multiplying both sides by 5 to make the 5 a fraction put 5 over 1
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\n" ); document.write( "2x/5 times 5/1 the fives cancel so you have 2x/1 or 2x \r
\n" ); document.write( "\n" ); document.write( "-10 times 5= -50
\n" ); document.write( "so
\n" ); document.write( "2x= -50
\n" ); document.write( "now divide both sides by 2
\n" ); document.write( "2x/2=1x or x
\n" ); document.write( "-50/2= -25
\n" ); document.write( "x=-25\r
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\n" ); document.write( "\n" ); document.write( "just to show you:
\n" ); document.write( "2x/5 times 5/1= 2x
\n" ); document.write( "-10 times 5= -50\r
\n" ); document.write( "\n" ); document.write( "2x= -50\r
\n" ); document.write( "\n" ); document.write( "2x/2=x
\n" ); document.write( "-50/2= -25\r
\n" ); document.write( "\n" ); document.write( "x= -25
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