document.write( "Question 702563: graph of y=sec(x- pi/2) \n" ); document.write( "
Algebra.Com's Answer #433053 by lwsshak3(11628)\"\" \"About 
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graph of sec: y=(Bx-C), period=2π/B, phase shift=C/B
\n" ); document.write( "For given function: y=sec(x- pi/2)
\n" ); document.write( "B=1
\n" ); document.write( "C=π/2
\n" ); document.write( "period=2π/B=2π
\n" ); document.write( "1/4 period=π/2
\n" ); document.write( "Phase shift=C/B=π/2 (shift to the right)
\n" ); document.write( "..
\n" ); document.write( "Graph for 1 period:
\n" ); document.write( "coordinates of basic sec function with no phase shift
\n" ); document.write( "(0,1), (π/2, ∞), (π, -1), (3π/2,-∞), (π/2,1)
\n" ); document.write( "Asymptotes:x=π/2 and x=3π/2
\n" ); document.write( "..
\n" ); document.write( "π/2 phase shift to the right
\n" ); document.write( "(0,∞), (π/2,1), (π, ∞), (3π/2, -1), (2π,-∞), (5π/2,1)
\n" ); document.write( "asymptotes: x=0, x=π, x=2π \n" ); document.write( "
\n" );