document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62539>Question 62539</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The period of a simple pendulum is directly proportional to the square root of its length.  If a pendulum has a length of 6 feet and a period of 2 seconds, to what length should it be shortened to achieve a 1 second period. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43304 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The period of a simple pendulum is directly proportional to the square root of its length. If a pendulum has a length of 6 feet and a period of 2 seconds, to what length should it be shortened to achieve a 1 second period.<BR>\n" );
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document.write( "P=ksqrt(L)<BR>\n" );
document.write( "If L=6 and P=2 sec, then <BR>\n" );
document.write( "2=ksqrt6<BR>\n" );
document.write( "k=2/sqrt(6)<BR>\n" );
document.write( "k is the constant of proportionality for this particular pendulum.<BR>\n" );
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document.write( "Formula: <BR>\n" );
document.write( "Period = (2/sqrt6)sqrt(L)<BR>\n" );
document.write( "If P = 1 second, then<BR>\n" );
document.write( "1=(2/sqrt6)sqrtL<BR>\n" );
document.write( "sqrtL=(sqrt6/2)<BR>\n" );
document.write( "L=[(sqrt6/2]^2<BR>\n" );
document.write( "L=6/4=3/2 or 1.5 ft.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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