document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=702431>Question 702431</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I find the altitude of an equilateral triangle whose perimeter is 60 meters? I think you're supposed to divide the triangle by 3 because it has 3 sides and then multiply that answer by one half to get the altitude, is this correct? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #432984 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=432984\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 60/3 = 20\r<BR>\n" );
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document.write( "Each side is 20 meters.\r<BR>\n" );
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document.write( "Then you cut this side in half to get 10 meters. Draw a perpendicular line from one vertex to the midpoint of the opposite side. Call this length h (for height)\r<BR>\n" );
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document.write( "By the pythagorean theorem\r<BR>\n" );
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document.write( "h^2 + 10^2 = 20^2\r<BR>\n" );
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document.write( "h^2 + 100 = 400\r<BR>\n" );
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document.write( "h^2 = 400 - 100\r<BR>\n" );
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document.write( "h^2 = 300\r<BR>\n" );
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document.write( "h = sqrt(300)\r<BR>\n" );
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document.write( "h = sqrt(100*3)\r<BR>\n" );
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document.write( "h = sqrt(100)*sqrt(3)\r<BR>\n" );
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document.write( "h = 10*sqrt(3)\r<BR>\n" );
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document.write( "So the height or altitude is exactly 10*sqrt(3) meters long. </SPAN>\n" );
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