document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=702398>Question 702398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square's side is increased by 3 yards, which corresponds to an increase in the area by 69 square yards. How many yards is the side of the initial square? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #432953 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=432953\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+3)^2 = x^2 + 69\r<BR>\n" );
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document.write( "x^2 + 6x + 9 = x^2 + 69\r<BR>\n" );
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document.write( "x^2 + 6x + 9 - x^2 = x^2 + 69 - x^2\r<BR>\n" );
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document.write( "6x + 9 = 69\r<BR>\n" );
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document.write( "6x = 69 - 9\r<BR>\n" );
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document.write( "6x = 60\r<BR>\n" );
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document.write( "x = 60/6\r<BR>\n" );
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document.write( "x = 10\r<BR>\n" );
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document.write( "The initial square had a side length of 10 yards. </SPAN>\n" );
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