document.write( "Question 62529: A bicyclist and a hiker leave the same place at the same time and travel in the same direction. The bicyclist travels three times as fast as the hiker. At the end of 3hr they are 24 miles apart. How fast does the hiker travel. \n" ); document.write( "
Algebra.Com's Answer #43295 by uma(370)![]() ![]() ![]() You can put this solution on YOUR website! Let the speed of the hiker be x mph \n" ); document.write( "So speed of the bicyclist = 3x mph \n" ); document.write( "Distance travelled by the hiker in 3 hrs = 3x miles. \n" ); document.write( "Distance travelled by the bicyclist in 3 hrs = 3*3x \n" ); document.write( " = 9x miles.\r \n" ); document.write( "\n" ); document.write( "Distance they are apart = 24 miles.\r \n" ); document.write( "\n" ); document.write( "==> 9x - 3x = 24 \n" ); document.write( "==> 6x = 24 \n" ); document.write( "==> 6x/6 = 24/6 \n" ); document.write( "==> x = 4\r \n" ); document.write( "\n" ); document.write( "==> the hiker travels at 4 mph.\r \n" ); document.write( "\n" ); document.write( "Good Luck!!! \n" ); document.write( " |