document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62523>Question 62523</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi can you please help me in solving these equations thank you\r<BR>\n" );
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document.write( "1.what are the values of x and y if the following are both true<BR>\n" );
document.write( "3x - 2y = 3<BR>\n" );
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document.write( " x + 4y = 29\r<BR>\n" );
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document.write( "2. which pair of values satisfies the equation<BR>\n" );
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document.write( "    4x - y = 12<BR>\n" );
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document.write( "    3x - 2y = 14\r<BR>\n" );
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document.write( "3. Use the trial and improvement method to solve the equation 2x + 5 = 24. Find a solution that is a positive number and give your answer to 1 d.p. <BR>\n" );
document.write( "* i could not fit the power of 3 on top of 2x so 2x has a power of three\r<BR>\n" );
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document.write( "Thank you hope you can help me answereing these 3 sets of questions for my homework  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43291 by </B><A HREF=/tutors/aboutme.mpl?userid=dolly><B>dolly(163)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dolly><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  1)We have 2 equations with us<BR>\n" );
document.write( "            3x-2y=3 ---------(1)<BR>\n" );
document.write( "            x+4y=29 ---------(2)\r<BR>\n" );
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document.write( " From equation (2) we first find what is x<BR>\n" );
document.write( " subtracting 4y on both sides<BR>\n" );
document.write( "==> x+4y-4y=29-4y<BR>\n" );
document.write( "==> x=29-4y -----(3)<BR>\n" );
document.write( " We substitute this value of x in equation (1)<BR>\n" );
document.write( "we get,  3(29-4y)-2y=3<BR>\n" );
document.write( "      ==> 87-12y-2y=3<BR>\n" );
document.write( "      Subtracting 87 on both sides we get,<BR>\n" );
document.write( "      87-87-12y-2y=3-87<BR>\n" );
document.write( "  ==> -12y-2y=-84 <BR>\n" );
document.write( "  ==> -14y=-84<BR>\n" );
document.write( " Now dividing both sides by -14,<BR>\n" );
document.write( "   (-14/-14)y=(-84/-14)<BR>\n" );
document.write( "  ==> y=+6<BR>\n" );
document.write( "  From (3) we substitute the value oy y=6 to find x<BR>\n" );
document.write( "==>  x=29-4y<BR>\n" );
document.write( "==>  x=29-(4*6)<BR>\n" );
document.write( "  ==> x=29-24<BR>\n" );
document.write( "==> x=+5<BR>\n" );
document.write( "The values of x and y are +5 and +6.\r<BR>\n" );
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document.write( "2) We have 2 equations with us<BR>\n" );
document.write( "            4x-y=12---------(1)<BR>\n" );
document.write( "            3x-2y=14 ---------(2)\r<BR>\n" );
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document.write( " From equation (1) we find what y is<BR>\n" );
document.write( " subtracting 4x on both sides, we get<BR>\n" );
document.write( "   -4x+4x-y=12-4x<BR>\n" );
document.write( "==> -y=12-4x<BR>\n" );
document.write( "Dividing by -1 on both sides we get<BR>\n" );
document.write( " -y/-1=(12-4x)/-1<BR>\n" );
document.write( "==> y=-12+4x ----(3)<BR>\n" );
document.write( "Substituting this value of y in equation (2)\r<BR>\n" );
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document.write( "     3x-2(-12+4x)=14<BR>\n" );
document.write( "==>  3x+24-8x=14<BR>\n" );
document.write( "==>  -5x+24=14<BR>\n" );
document.write( "subtracting -24 on both sides, we get<BR>\n" );
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document.write( "     -24+24-5x=14-24<BR>\n" );
document.write( "  ==> -5x=-10<BR>\n" );
document.write( "Dividing on both sides by -5,<BR>\n" );
document.write( " -5x/-5=-10/-5<BR>\n" );
document.write( "==>  x=2<BR>\n" );
document.write( "Substituting this value of x in equation (3)\r<BR>\n" );
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document.write( "  ==> y=-12+4x<BR>\n" );
document.write( " ==> x=-12+4*2<BR>\n" );
document.write( "==> x=-12+8<BR>\n" );
document.write( "  ==>x=-4<BR>\n" );
document.write( "The values of x and y are 2 and -4.\r<BR>\n" );
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document.write( "3) 2x+5=24 where 2x is to power 3\r<BR>\n" );
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document.write( "  2x^3+5=24<BR>\n" );
document.write( " subtracting 5 on both sides <BR>\n" );
document.write( " 2x^3+5-5=24-5<BR>\n" );
document.write( "==> 2x^3=19<BR>\n" );
document.write( " dividing by 2 on both sides we get,<BR>\n" );
document.write( "  (2x^3)/2=19/2<BR>\n" );
document.write( "==> x^3=9.5<BR>\n" );
document.write( " Finding the cube root of 9.5 we get the value of x<BR>\n" );
document.write( "==> x=2.1\r<BR>\n" );
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document.write( " </SPAN>\n" );
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