document.write( "Question 7860: Please help me with this mixture problem. I have no idea how to do it. THanks
\n" );
document.write( "A car radiator contains 10 liters of a 30% antifreeze solution. how many liters will have to be replaced with pure antifreeze if the resulting solution is to be 50% antifreeze? \n" );
document.write( "
Algebra.Com's Answer #4329 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let x = the number of liters of antifreeze that must be replaced. Change percentages to decimals.\r \n" ); document.write( "\n" ); document.write( "Start with 10 liters of 30% antifreeze. Write this as: 0.3(10) \n" ); document.write( "You want to remove x liters of 30% antifreeze. Write this as -0.3(x) \n" ); document.write( "Then you want add x liters of 100% antifreeze. Write this as +1(x) or just +x.\r \n" ); document.write( "\n" ); document.write( "Now all of this must add up to 10 liters of 50% antifreeze. Write this as 0.5(10). \n" ); document.write( "Putting it all together, we have:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You must remove 2.86 liters of 30% antifreeze then add 2.86 liters of 100% antifreeze. \n" ); document.write( " \n" ); document.write( " |