document.write( "Question 7860: Please help me with this mixture problem. I have no idea how to do it. THanks
\n" ); document.write( "A car radiator contains 10 liters of a 30% antifreeze solution. how many liters will have to be replaced with pure antifreeze if the resulting solution is to be 50% antifreeze?
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Algebra.Com's Answer #4329 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let x = the number of liters of antifreeze that must be replaced. Change percentages to decimals.\r
\n" ); document.write( "\n" ); document.write( "Start with 10 liters of 30% antifreeze. Write this as: 0.3(10)
\n" ); document.write( "You want to remove x liters of 30% antifreeze. Write this as -0.3(x)
\n" ); document.write( "Then you want add x liters of 100% antifreeze. Write this as +1(x) or just +x.\r
\n" ); document.write( "\n" ); document.write( "Now all of this must add up to 10 liters of 50% antifreeze. Write this as 0.5(10).
\n" ); document.write( "Putting it all together, we have:\r
\n" ); document.write( "\n" ); document.write( "\"0.3%2810%29+-+0.3x+%2B+x+=+0.5%2810%29\" Simplify and solve for x.\r
\n" ); document.write( "\n" ); document.write( "\"3+%2B+0.7x+=+5\"\r
\n" ); document.write( "\n" ); document.write( "\"0.7x+=+2\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+2.86+\"\r
\n" ); document.write( "\n" ); document.write( "You must remove 2.86 liters of 30% antifreeze then add 2.86 liters of 100% antifreeze.
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