document.write( "Question 702308: Carla is 5 years old and Jim is 13 years younger than Peter. One year ago, Peter's age was twice the sum of Carla's & Jim's age. Find the present age of each one of them.
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Algebra.Com's Answer #432896 by ankor@dixie-net.com(22740)\"\" \"About 
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Carla is 5 years old and Jim is 13 years younger than Peter.
\n" ); document.write( "c = 5
\n" ); document.write( "j = p - 13
\n" ); document.write( "or
\n" ); document.write( "p = j + 13
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\n" ); document.write( " One year ago, Peter's age was twice the sum of Carla's & Jim's age.
\n" ); document.write( "one year ago c = 4
\n" ); document.write( "p - 1 = 2[j-1+4]
\n" ); document.write( "p - 1 = 2(j+3)
\n" ); document.write( "p - 1 = 2j + 6
\n" ); document.write( "p = 2j + 6 + 1
\n" ); document.write( "p = 2j + 7
\n" ); document.write( "replace p with (j+13)
\n" ); document.write( "j + 13 = 2j + 7
\n" ); document.write( "13 - 7 = 2j - j
\n" ); document.write( "j = 6 yrs old is Jim
\n" ); document.write( "then
\n" ); document.write( "p = 6 + 13
\n" ); document.write( "p = 19 yrs old is Peter\r
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\n" ); document.write( "\n" ); document.write( " Find the present age of each one of them. c=5, p=19, j=6 \n" ); document.write( "
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