document.write( "Question 702244: Please help me solve this linear equation using substitution.\r
\n" ); document.write( "\n" ); document.write( "0.6x - 0.2y = -0.2
\n" ); document.write( "-0.03x - 0.07y = 0.17\r
\n" ); document.write( "\n" ); document.write( "Thank you.
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Algebra.Com's Answer #432887 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
This system,
\n" ); document.write( "0.6x - 0.2y = -0.2
\n" ); document.write( "-0.03x - 0.07y = 0.17\r
\n" ); document.write( "\n" ); document.write( "will be a bit more comfortable if you multiply the entire first equation by 10, and the entire second equation by -100.\r
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\n" ); document.write( "\n" ); document.write( "You will then have the equivalent system,
\n" ); document.write( "6x-2y=-2
\n" ); document.write( "3x+7y=-17\r
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\n" ); document.write( "\n" ); document.write( "Solve either equation for x OR y; substitute the found expression into the other equation and solve for the other variable. You now will have one of the values for that variable.\r
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\n" ); document.write( "\n" ); document.write( "As example of a way to do the process, I pick the second equation and solve for y:
\n" ); document.write( "7y=-17-3x
\n" ); document.write( "y=(-17-3x)/7\r
\n" ); document.write( "\n" ); document.write( "Let me put this expression for y into the first equation.
\n" ); document.write( "6x-2(y)=-2
\n" ); document.write( "6x-2((-17-3x)/7)=-2
\n" ); document.write( "OR
\n" ); document.write( "\"6%2Ax-2%2A%28%28-17-3%2Ax%29%2F7%29=-2\"\r
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\n" ); document.write( "\n" ); document.write( "Now solve for x,.....continue until done....!\r
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\n" ); document.write( "\n" ); document.write( "... a little bit further into the process,
\n" ); document.write( "clear the fraction by multiplying both sides by 7:
\n" ); document.write( "\"42%2Ax-2%28-17-3%2Ax%29=-14\"
\n" ); document.write( "\"43%2Ax%2B34%2B6%2Ax=-14\"
\n" ); document.write( "\"48%2Ax=-34-14\"
\n" ); document.write( "\"48%2Ax=-48\",
\n" ); document.write( "\"x=-1\"...... You can continue on from here...
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