document.write( "Question 702244: Please help me solve this linear equation using substitution.\r
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document.write( "0.6x - 0.2y = -0.2
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document.write( "-0.03x - 0.07y = 0.17\r
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document.write( "Thank you. \n" );
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Algebra.Com's Answer #432887 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! This system, \n" ); document.write( "0.6x - 0.2y = -0.2 \n" ); document.write( "-0.03x - 0.07y = 0.17\r \n" ); document.write( "\n" ); document.write( "will be a bit more comfortable if you multiply the entire first equation by 10, and the entire second equation by -100.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You will then have the equivalent system, \n" ); document.write( "6x-2y=-2 \n" ); document.write( "3x+7y=-17\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve either equation for x OR y; substitute the found expression into the other equation and solve for the other variable. You now will have one of the values for that variable.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As example of a way to do the process, I pick the second equation and solve for y: \n" ); document.write( "7y=-17-3x \n" ); document.write( "y=(-17-3x)/7\r \n" ); document.write( "\n" ); document.write( "Let me put this expression for y into the first equation. \n" ); document.write( "6x-2(y)=-2 \n" ); document.write( "6x-2((-17-3x)/7)=-2 \n" ); document.write( "OR \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now solve for x,.....continue until done....!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "... a little bit further into the process, \n" ); document.write( "clear the fraction by multiplying both sides by 7: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |