document.write( "Question 702267: Given that f\"(x)=\"3x%5E2-2\" , \"f%282%29=-1\" , f'(-1)=5 , find \"f%28x%29\".\r
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Algebra.Com's Answer #432875 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
f '' (x) = 3x^2 - 2\r
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\n" ); document.write( "\n" ); document.write( "Integrate both sides to get\r
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\n" ); document.write( "\n" ); document.write( "f ' (x) = x^3 - 2x + C\r
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\n" ); document.write( "\n" ); document.write( "We're told that f ' (-1) = 5, so\r
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\n" ); document.write( "\n" ); document.write( "f ' (x) = x^3 - 2x + C\r
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\n" ); document.write( "\n" ); document.write( "f ' (-1) = (-1)^3 - 2(-1) + C\r
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\n" ); document.write( "\n" ); document.write( "5 = -1 + 2 + C\r
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\n" ); document.write( "\n" ); document.write( "5 = 1 + C\r
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\n" ); document.write( "\n" ); document.write( "5 - 1 = C\r
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\n" ); document.write( "\n" ); document.write( "4 = C\r
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\n" ); document.write( "\n" ); document.write( "C = 4\r
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\n" ); document.write( "\n" ); document.write( "So f ' (x) = x^3 - 2x + 4\r
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\n" ); document.write( "\n" ); document.write( "Integrate both sides to get\r
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\n" ); document.write( "\n" ); document.write( "f(x) = (1/4)*x^4 - x^2 + 4x + C\r
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\n" ); document.write( "\n" ); document.write( "Now use the fact that f(2) = -1\r
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\n" ); document.write( "\n" ); document.write( "f(x) = (1/4)*x^4 - x^2 + 4x + C\r
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\n" ); document.write( "\n" ); document.write( "f(2) = (1/4)*(2)^4 - (2)^2 + 4(2) + C\r
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\n" ); document.write( "\n" ); document.write( "f(2) = (1/4)*(16) - 4 + 4(2) + C\r
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\n" ); document.write( "\n" ); document.write( "f(2) = 4 - 4 + 8 + C\r
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\n" ); document.write( "\n" ); document.write( "f(2) = 8 + C\r
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\n" ); document.write( "\n" ); document.write( "-1 = 8 + C\r
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\n" ); document.write( "\n" ); document.write( "-1 - 8 = C\r
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\n" ); document.write( "\n" ); document.write( "-9 = C\r
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\n" ); document.write( "\n" ); document.write( "C = -9\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the function f(x) is \"f%28x%29+=+expr%281%2F4%29%2Ax%5E4+-+x%5E2+%2B+4x+-+9\"
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