document.write( "Question 702146: A domed ceiling is a parabolic surface. FOr the best lighting on the floor, a light source is to be placed at the focus of the surface. If 5 m down from the top of the dome ceiling is 3 m wide, find the best location for the light source. \n" ); document.write( "
Algebra.Com's Answer #432859 by lwsshak3(11628)\"\" \"About 
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A domed ceiling is a parabolic surface. FOr the best lighting on the floor, a light source is to be placed at the focus of the surface. If 5 m down from the top of the dome ceiling is 3 m wide, find the best location for the light source.
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\n" ); document.write( "Draw a parabola facing down with the vertex (top of the dome) at the origin (0,0)
\n" ); document.write( "Equation for this parabola: x^2=-4py
\n" ); document.write( "Using coordinates (1.5,-5), 5 m down from the top where the ceiling is 3 m wide,
\n" ); document.write( "x^2=4py
\n" ); document.write( "1.5^2=-4p(-5)
\n" ); document.write( "2.25/5=4p
\n" ); document.write( "4p=0.45
\n" ); document.write( "p=0.1125
\n" ); document.write( "location for the light source: 0.1125 m below the dome(vertex) on the axis of symmetry(x=0)
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