document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46266>Question 46266</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ooops! sent the other one too soon.  I have to show my work with this problem- can you show me how to do it rather than just give me the answer so I do the others in the book, please?\r<BR>\n" );
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document.write( "Simplify:\r<BR>\n" );
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document.write( "-[-(-1)15]  (that *15* means the power of 15)  So since the answer without the *15* would be -1, then with the 15th power would it be -15 since negative times a positive is a negative?\r<BR>\n" );
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document.write( "Thank you!\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43283 by </B><A HREF=/tutors/aboutme.mpl?userid=mystic1306><B>mystic1306(20)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mystic1306><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43283\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if your question is -[-(-1)]to the 15th power try this<BR>\n" );
document.write( "first multiply out the negitives <BR>\n" );
document.write( "- times - equals postive (+)<BR>\n" );
document.write( "+ times - is negitive (-)<BR>\n" );
document.write( "so you have -1^15<BR>\n" );
document.write( "15 is an odd number your answer will be negitive<BR>\n" );
document.write( "so you go <BR>\n" );
document.write( "-1*-1*-1*-1*-1*-1*-1*-1*-1*-1*-1*-1*-1*-1*-1= -1\r<BR>\n" );
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document.write( "* means multiply\r<BR>\n" );
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document.write( "multiply -1 times -1  15 times </SPAN>\n" );
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