document.write( "Question 702085: Can you please help me solve this linear equation using substitution.\r
\n" ); document.write( "\n" ); document.write( "1/2x + 3y = 5/6
\n" ); document.write( "1/3x - 5y = 16/9\r
\n" ); document.write( "\n" ); document.write( "Thank you.
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Algebra.Com's Answer #432771 by sofiyac(983)\"\" \"About 
You can put this solution on YOUR website!
1/2x + 3y = 5/6 we will subtract 1/2x from both sides of this equation
\n" ); document.write( "1/3x - 5y = 16/9 *
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\n" ); document.write( "3y = 5/6-1/2x next we divide both sides by 3
\n" ); document.write( "y = 5/18-1/6x ** now we plug this into the equation marked with *
\n" ); document.write( "1/3x-5(5/18-1/6x)=16/9 next we keep simplifying this one, multiply out the 5
\n" ); document.write( "1/3x-25/18+5/6x=16/9 combine like terms
\n" ); document.write( "7/6x=19/6 multiply both sides by 6/7
\n" ); document.write( "x=19/7 now that we have x we need to plug it back into equation marked with **
\n" ); document.write( "y=5/18-19/7(1/6) simplify
\n" ); document.write( "y=5/18-19/42
\n" ); document.write( "\"y=%2835-57%29%2F126\"
\n" ); document.write( "\"y=%28-22%29%2F126\" reduce top and bottom by 2
\n" ); document.write( "\"y=-11%2F63\"
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