document.write( "Question 702052: i'm trying to help my son with his math via video chat. It's been 15 years since I've attempted any type of math like this.\r
\n" ); document.write( "\n" ); document.write( "8y-3(5+2y)=85-3x\r
\n" ); document.write( "\n" ); document.write( "I'm stumped.
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Algebra.Com's Answer #432767 by josgarithmetic(39799)\"\" \"About 
You can put this solution on YOUR website!
8y-3(5+2y)=85-3x\r
\n" ); document.write( "\n" ); document.write( "Take care of multiplications and divisions first; and then deal with additions and subtractions.\r
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\n" ); document.write( "\n" ); document.write( "Steps may vary,....
\n" ); document.write( "8y-15-6y=85-3x
\n" ); document.write( "8y-6y-15=85-3x
\n" ); document.write( "+3x+2y-15=85-3x+3x
\n" ); document.write( "3x+2y-15+15=85+0+15
\n" ); document.write( "3x+2y=100\r
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\n" ); document.write( "\n" ); document.write( "PostNote - Are you SURE the x is not supposed to be a y instead? If it IS supposed to be y, then you'd really end up with 3y+2y=100, then you would add the terms of y:
\n" ); document.write( "\"5y=100\"
\n" ); document.write( "\"%285y%29%2F5=100%2F5\"
\n" ); document.write( "\"y=20\".\r
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\n" ); document.write( "\n" ); document.write( "Your original shown equation had two variables, x and y.
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