document.write( "Question 702052: i'm trying to help my son with his math via video chat. It's been 15 years since I've attempted any type of math like this.\r
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document.write( "8y-3(5+2y)=85-3x\r
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document.write( "I'm stumped. \n" );
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Algebra.Com's Answer #432767 by josgarithmetic(39799) ![]() You can put this solution on YOUR website! 8y-3(5+2y)=85-3x\r \n" ); document.write( "\n" ); document.write( "Take care of multiplications and divisions first; and then deal with additions and subtractions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Steps may vary,.... \n" ); document.write( "8y-15-6y=85-3x \n" ); document.write( "8y-6y-15=85-3x \n" ); document.write( "+3x+2y-15=85-3x+3x \n" ); document.write( "3x+2y-15+15=85+0+15 \n" ); document.write( "3x+2y=100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "PostNote - Are you SURE the x is not supposed to be a y instead? If it IS supposed to be y, then you'd really end up with 3y+2y=100, then you would add the terms of y: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your original shown equation had two variables, x and y. \n" ); document.write( " |