document.write( "Question 702059: Hi, I need help in solving this question.
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document.write( " 5:3 and the losers scored 77 points, how many does the other team have?
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Algebra.Com's Answer #432764 by RedemptiveMath(80)![]() ![]() ![]() You can put this solution on YOUR website! I'm assuming that 5:3 is the ratio of the winning team's score to the losing team's score. Therefore, the ratio of these two scores must be equivalent to 5:3, or the fractions 5/3 and winning/losing (scores) must be equal. (Ratios can be written as fractions.) Since we do not know the winning team's score, we can use a variable to stand in its place. We can solve for this variable by using cross multiplication:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5/3 = x/77 \n" ); document.write( "3x = 385 \n" ); document.write( "x ≈ 128.3 points.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Rounding down, the winning team would have 128 points if the losing team had 77 and the ratio between them is 5:3. \n" ); document.write( " |