document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62496>Question 62496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One type of gasohol is 10% alcohol and another type is 35% alcohol. How much of each type must be mixed to obtain 400 gallons of a 25% alcohol mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43273 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43273\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One type of gasohol is 10% alcohol( T SAY) and another type is 35% alcohol(F SAY). How much of each type must be mixed to obtain 400 gallons of a 25% alcohol mixture?<BR>\n" );
document.write( "T+F = 400 G......F =  400 - T G....................1<BR>\n" );
document.write( "ALCOHOL IN T = T*10/100=0.1T G.....................2<BR>\n" );
document.write( "ALCOHOL IN F = F*35/100=0.35F=0.35(400-T)=140-0.35T G.............3<BR>\n" );
document.write( "TOTAL ALCOHOL IN THE MIX = 400*25/100=100 G.................4<BR>\n" );
document.write( "HENCE<BR>\n" );
document.write( "0.1T+140-0.35T=100<BR>\n" );
document.write( "0.35T-0.1T=140-100=40<BR>\n" );
document.write( "0.25T = 40<BR>\n" );
document.write( "T=40/0.25=160 G............IS 10% ALCOHOL IN THE MIX<BR>\n" );
document.write( "F=400-160=240 G............IS 35% ALCOHOL IN THE MIX </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );