document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=702005>Question 702005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bill Phipps is 6 times as old as his 5-year old niece. How long will it be before he is twice as old as she?\r<BR>\n" );
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document.write( "Thanks for your help :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #432713 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=432713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Bill Phipps is 6 times as old as his 5-year old niece\r<BR>\n" );
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document.write( "So Bill is 6*5 = 30 years old\r<BR>\n" );
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document.write( "In x years, he will be 30+x years old\r<BR>\n" );
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document.write( "In x years, she will be 5+x years old\r<BR>\n" );
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document.write( "If you want to know when he will be twice her age, simply say\r<BR>\n" );
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document.write( "30+x = 2(5+x)\r<BR>\n" );
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document.write( "Then solve for x\r<BR>\n" );
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document.write( "30+x=2(5+x)\r<BR>\n" );
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document.write( "30+x=10+2x\r<BR>\n" );
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document.write( "x=10+2x-30\r<BR>\n" );
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document.write( "x-2x=10-30\r<BR>\n" );
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document.write( "-x=10-30\r<BR>\n" );
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document.write( "-x=-20\r<BR>\n" );
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document.write( "x=(-20)/(-1)\r<BR>\n" );
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document.write( "x=20\r<BR>\n" );
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document.write( "So it will take 20 years for him to be twice as old as her.\r<BR>\n" );
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document.write( "Notice how adding 20 years to 30 makes him now 50. Adding the same 20 years to 5 makes her now 25. Finally, notice that 50 is double of 25. So the answer checks. </SPAN>\n" );
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