document.write( "Question 701981: How man milliliters of 100% acid must be added to 50 milliliters of a 40% acid solution to obtain a 50% acid solution? \r
\n" );
document.write( "\n" );
document.write( "I had set up and figured the problem like this:\r
\n" );
document.write( "\n" );
document.write( "1(x)+.4(50)=.5(50+x)
\n" );
document.write( "20x=25+.5x
\n" );
document.write( "19.25x=25
\n" );
document.write( "x=50/39 mL\r
\n" );
document.write( "\n" );
document.write( "But I have a gut feeling that x does not equal 50/39.
\n" );
document.write( "What did I do wrong?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #432679 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! How much pure acid will be in the solution? Letting x equal how much of the 100% material to add, \n" ); document.write( "Pure acid in the resulting solution is 1*x+50*(0.40).\r \n" ); document.write( "\n" ); document.write( "How much solution must result when the two parts are added and mixed? \n" ); document.write( "The amount of resulting solution is x+50 milliliters.\r \n" ); document.write( "\n" ); document.write( "You want a result of 50% acid, or as fraction, 0.5 as acid.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Solve for x.\r \n" ); document.write( "\n" ); document.write( "Skipping a step,... \n" ); document.write( " \n" ); document.write( "Continue....Finish... \n" ); document.write( " |