document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=701981>Question 701981</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How man milliliters of 100% acid must be added to 50 milliliters of a 40% acid solution to obtain a 50% acid solution? \r<BR>\n" );
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document.write( "I had set up and figured the problem like this:\r<BR>\n" );
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document.write( "1(x)+.4(50)=.5(50+x)<BR>\n" );
document.write( "20x=25+.5x<BR>\n" );
document.write( "19.25x=25<BR>\n" );
document.write( "x=50/39 mL\r<BR>\n" );
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document.write( "But I have a gut feeling that x does not equal 50/39.<BR>\n" );
document.write( "What did I do wrong? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #432675 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=432675\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1(x)+.4(50)=.5(50+x)\r<BR>\n" );
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document.write( "x+20=25+0.5x\r<BR>\n" );
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document.write( "x - 0.5x = 25 - 20\r<BR>\n" );
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document.write( "0.5x = 5\r<BR>\n" );
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document.write( "x = 5/(0.5)\r<BR>\n" );
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document.write( "x = 10\r<BR>\n" );
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document.write( "So you need to add 10 mL of 100% acid </SPAN>\n" );
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