document.write( "Question 701863: I can't figure this question out:
\n" ); document.write( "The area of a rectangle is 256 m. The length of the rectangle is 4 times greater than the width. What are the length and width of the triangle. \n" ); document.write( "

Algebra.Com's Answer #432659 by Simnepi(216) $\"\"$ $\"About$

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let the width of the rectangle be called x.
\n" ); document.write( "since the length is 4 times the width, the length will be 4x.
\n" ); document.write( "Now, area = length times width for a rectangle.
\n" ); document.write( "so the area of this rectangle, 256 square metres, is 4x times x, that is
\n" ); document.write( " $\"4x%5E2+=+256\"$
\n" ); document.write( "dividing by 4 gives
\n" ); document.write( " $\"x%5E2+=+64\"$
\n" ); document.write( "to find x we have to 'undo' the squaring of x by taking the square root.
\n" ); document.write( "so $\"sqrt%2864%29+=+8\"$
\n" ); document.write( "therefore x = 8.
\n" ); document.write( "which means that the width is 8m and the length is 32m \n" ); document.write( "

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