document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=701927>Question 701927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When you are dividing a fraction within a fraction and you use the recipricol to mulitply, for this question it is (5/7)/(2&#8730;6/7) how would you multiply the square root? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #432655 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=432655\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When you are dividing a fraction within a fraction and you use the recipricol to multiply, for this question it is (5/7)/(2&#8730;6/7) how would you multiply the square root?<BR>\n" );
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document.write( "If the 6/7 fraction is in the radical it equalt sqrt(42)/7.<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "(5/7)/(2sqrt(42)/7)<BR>\n" );
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document.write( "Inverting the denominator results in canceling the common 7's.<BR>\n" );
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document.write( "You get: = 5/(2sqrt(42))<BR>\n" );
document.write( "Simplifying that you get:<BR>\n" );
document.write( "= (5sqrt(42)/2*42)<BR>\n" );
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document.write( "= (5sqrt(42)/84<BR>\n" );
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document.write( "= (5/84)sqrt(42)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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