document.write( "Question 701855: how would I graph
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Algebra.Com's Answer #432618 by mouk(232)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a linear system of equations by subsitution

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"1%2Ax%2B1%2Ay=4\"
\n" ); document.write( " \"2%2Ax%2B1%2Ay=6\"
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\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
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\n" ); document.write( " Solve for y for the first equation
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\n" ); document.write( " \"1%2Ay=4-1%2Ax\"Subtract \"1%2Ax\" from both sides
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\n" ); document.write( " \"y=%284-1%2Ax%29\" Divide both sides by 1.
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\n" ); document.write( " Which breaks down and reduces to
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\n" ); document.write( " \"y=4-1%2Ax\" Now we've fully isolated y
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\n" ); document.write( " Since y equals \"4-1%2Ax\" we can substitute the expression \"4-1%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
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\n" ); document.write( " \"2%2Ax%2B1%2Ahighlight%28%284-1%2Ax%29%29=6\" Replace y with \"4-1%2Ax\". Since this eliminates y, we can now solve for x.
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\n" ); document.write( " \"2%2Ax%2B1%2A%284%29%2B1%28-1%29x=6\" Distribute 1 to \"4-1%2Ax\"
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\n" ); document.write( " \"2%2Ax%2B4-1%2Ax=6\" Multiply
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\n" ); document.write( " \"2%2Ax%2B4-1%2Ax=6\" Reduce any fractions
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\n" ); document.write( " \"2%2Ax-1%2Ax=6-4\" Subtract \"4\" from both sides
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\n" ); document.write( " \"2%2Ax-1%2Ax=2\" Combine the terms on the right side
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\n" ); document.write( " \"1%2Ax=2\" Now combine the terms on the left side.
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\n" ); document.write( " \"cross%28%281%2F1%29%281%2F1%29%29x=%282%2F1%29%281%2F1%29\" Multiply both sides by \"1%2F1\". This will cancel out \"1%2F1\" and isolate x
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\n" ); document.write( " So when we multiply \"2%2F1\" and \"1%2F1\" (and simplify) we get
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\n" ); document.write( " \"x=2\" <---------------------------------One answer
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\n" ); document.write( " Now that we know that \"x=2\", lets substitute that in for x to solve for y
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\n" ); document.write( " \"2%282%29%2B1%2Ay=6\" Plug in \"x=2\" into the 2nd equation
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\n" ); document.write( " \"4%2B1%2Ay=6\" Multiply
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\n" ); document.write( " \"1%2Ay=6-4\"Subtract \"4\" from both sides
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\n" ); document.write( " \"1%2Ay=2\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F1%29%281%29%29%2Ay=%282%2F1%29%281%2F1%29\" Multiply both sides by \"1%2F1\". This will cancel out 1 on the left side.
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\n" ); document.write( " \"y=2%2F1\" Multiply the terms on the right side
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\n" ); document.write( " \"y=2\" Reduce
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\n" ); document.write( " So this is the other answer
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\n" ); document.write( " \"y=2\"<---------------------------------Other answer
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\n" ); document.write( " So our solution is
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\n" ); document.write( " \"x=2\" and \"y=2\"
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\n" ); document.write( " which can also look like
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\n" ); document.write( " (\"2\",\"2\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"1%2Ax%2B1%2Ay=4\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"1%2Ax%2B1%2Ay=4\" (red) and \"2%2Ax%2B1%2Ay=6\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
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\n" ); document.write( " and we can see that the two equations intersect at (\"2\",\"2\"). This verifies our answer.
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\n" ); document.write( " Plug in (\"2\",\"2\") into the system of equations
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\n" ); document.write( " Let \"x=2\" and \"y=2\". Now plug those values into the equation \"1%2Ax%2B1%2Ay=4\"
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\n" ); document.write( " \"1%2A%282%29%2B1%2A%282%29=4\" Plug in \"x=2\" and \"y=2\"
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\n" ); document.write( " \"2%2B2=4\" Multiply
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\n" ); document.write( " \"4=4\" Add
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\n" ); document.write( " \"4=4\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"2\",\"2\") satisfies \"1%2Ax%2B1%2Ay=4\"
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\n" ); document.write( " Let \"x=2\" and \"y=2\". Now plug those values into the equation \"2%2Ax%2B1%2Ay=6\"
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\n" ); document.write( " \"2%2A%282%29%2B1%2A%282%29=6\" Plug in \"x=2\" and \"y=2\"
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\n" ); document.write( " \"4%2B2=6\" Multiply
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\n" ); document.write( " \"6=6\" Add
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\n" ); document.write( " \"6=6\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"2\",\"2\") satisfies \"2%2Ax%2B1%2Ay=6\"
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\n" ); document.write( " Since the solution (\"2\",\"2\") satisfies the system of equations
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\n" ); document.write( " \"1%2Ax%2B1%2Ay=4\"
\n" ); document.write( " \"2%2Ax%2B1%2Ay=6\"
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\n" ); document.write( " this verifies our answer.
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