document.write( "Question 701772: Solve: 3^x+1=100. Logarithm Problem. \n" ); document.write( "
Algebra.Com's Answer #432582 by unlockmath(1688)\"\" \"About 
You can put this solution on YOUR website!
Hello,
\n" ); document.write( "Let's rewrite this 3^x+1=100 as:
\n" ); document.write( "3^x=99
\n" ); document.write( "Log (base 3) 99 = x
\n" ); document.write( "x=4.1827 (approx)
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com
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