document.write( "Question 701751: For the following problem, clearly define the variable(s) and write an equation that could be used to solve the problem. What are the units of the answer.\r
\n" ); document.write( "\n" ); document.write( "Two tugboats that have the same speed in still water travel in opposite directions in a river with a constant current of 5 miles per hour. The tugboats departed at the same time from a refueling station; and after a period of time, one has traveled 30 miles downstream and the other has traveled 6 miles upstream. Determine the rate of each boat in still water.
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Algebra.Com's Answer #432578 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+s+\" = their speed in still water in mi/hr
\n" ); document.write( "\"+s+%2B+5+\" = tugboat's speed going with the current in mi/hr
\n" ); document.write( "\"+s+-+5+\" = tugboat's speed going against the current in mi/hr
\n" ); document.write( "--------------
\n" ); document.write( "Equation for tugboat going upstream:
\n" ); document.write( "(1) \"+6+=+%28+s+-+5+%29%2At+\"
\n" ); document.write( "Equation for tugboat going downstream:
\n" ); document.write( "(2) \"+30+=+%28+s+%2B+5+%29%2At+\"
\n" ); document.write( "--------------------
\n" ); document.write( "(1) \"+6+=+s%2At+-+5t+\"
\n" ); document.write( "(2) \"+30+=+s%2At+%2B+5t+\"
\n" ); document.write( "Subtract (1) from (2)
\n" ); document.write( "(2) \"+30+=+s%2At+%2B+5t+\"
\n" ); document.write( "(1) \"+-6+=+-s%2At+%2B+5t+\"
\n" ); document.write( "\"+24+=+10t+\"
\n" ); document.write( "\"+t+=+2.4+\" hrs
\n" ); document.write( "and
\n" ); document.write( "(1) \"+6+=+%28+s+-+5+%29%2A2.4+\"
\n" ); document.write( "(1) \"+6+=+2.4s+-+12+\"
\n" ); document.write( "(1) \"+2.4s+=+18+\"
\n" ); document.write( "(1) \"+s+=+7.5+\"
\n" ); document.write( "Their speeds in still water is 7.5 mi / hr
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+30+=+%28+s+%2B+5+%29%2At+\"
\n" ); document.write( "(2) \"+30+=+%28+7.5+%2B+5+%29%2A2.4+\"
\n" ); document.write( "(2) \"+30+=+12.5%2A2.4+\"
\n" ); document.write( "(2) \"+30+=+30+\"
\n" ); document.write( "OK
\n" ); document.write( "(1) \"+6+=+%28+s+-+5+%29%2At+\"
\n" ); document.write( "(1) \"+6+=+%28+7.5+-+5+%29%2A2.4+\"
\n" ); document.write( "(1) \"+6+=+2.5%2A2.4+\"
\n" ); document.write( "(1) \"+6+=+6+\"
\n" ); document.write( "OK
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