document.write( "Question 701641: How would you solve:\r
\n" ); document.write( "\n" ); document.write( "log (base 3)of 2+ log (base 3)of 7= log (base 3)of x\r
\n" ); document.write( "\n" ); document.write( "or \r
\n" ); document.write( "\n" ); document.write( "(1/4)log 15+ (1/2)log 49= logx\r
\n" ); document.write( "\n" ); document.write( "Either problem would be great! I really appreciate it, thanks so much. I really looked everywhere and tried numerous times, hopefully I can finally get the answer! Thanks! :)
\n" ); document.write( "

Algebra.Com's Answer #432505 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
log (base 3)of 2+ log (base 3)of 7= log (base 3)of x
\n" ); document.write( "\"log%283%2C2%29+%2B+log%283%2C7%29+=+log%283%2Cx%29\"
\n" ); document.write( "\"log%283%2C2%2A7%29+=+log%283%2Cx%29\"
\n" ); document.write( "\"log%283%2C14%29+=+log%283%2Cx%29\"
\n" ); document.write( "\"14+=+x\"
\n" ); document.write( "or
\n" ); document.write( "(1/4)log 15+ (1/2)log 49= logx
\n" ); document.write( "\"%281%2F4%29log%2810%29+%2B+%281%2F2%29log%2849%29+=+log%28x%29\"
\n" ); document.write( "\"log%2810%5E%281%2F4%29%29+%2B+log%2849%5E%281%2F2%29%29+=+log%28x%29\"
\n" ); document.write( "\"log%2810%5E%281%2F4%29%29+%2B+log%287%29+=+log%28x%29\"
\n" ); document.write( "\"log%287%2A10%5E%281%2F4%29%29+=+log%28x%29\"
\n" ); document.write( "\"7%2A10%5E%281%2F4%29+=+x\"
\n" ); document.write( "\"12.45+=+x\"
\n" ); document.write( "
\n" ); document.write( "
\n" );