document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=701631>Question 701631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> jack has 3 hours of homework. He will take one 30 minute brake. To finish by 9:00pm what is the latest time he can begin his homework? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #432491 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39613)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=432491\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hour 9 of the day minus hour t of the day is 3 hours plus 30 minutes. NO more than 30 minutes break; question is, \"what's the latest\" he can start.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9-t=3%2B%281%2F2%29 ALIGN=MIDDLE  ALT=\"9-t=3%2B%281%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >,   Find t.\r<BR>\n" );
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document.write( "-t=3+(1/2)-9<BR>\n" );
document.write( "t=9-3-(1/2),   just compute. </SPAN>\n" );
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