document.write( "Question 701633: x^3+4x^2+7x=28=0\r
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Algebra.Com's Answer #432490 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Assuming you meant to type: x^3+4x^2+7x+28 = 0 \r
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\n" ); document.write( "\n" ); document.write( "Possible Roots: List all the factors of 28\r
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\n" ); document.write( "\n" ); document.write( "Possible Roots: 1, 2, 4, 7, 14, 28, -1, -2, -4, -7, -14, -28\r
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\n" ); document.write( "\n" ); document.write( "Another Note: This trick only works if the leading coefficient is 1 or -1.\r
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\n" ); document.write( "\n" ); document.write( "x^3+4x^2+7x+28=0 \r
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\n" ); document.write( "\n" ); document.write( "(x^3+4x^2)+(7x+28)=0 \r
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\n" ); document.write( "\n" ); document.write( "x^2(x+4)+7(x+4)=0\r
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\n" ); document.write( "\n" ); document.write( "(x^2+7)(x+4) = 0\r
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\n" ); document.write( "\n" ); document.write( "x^2+7 = 0 or x+4 = 0\r
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\n" ); document.write( "\n" ); document.write( "x^2 = -7 or x = -4\r
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\n" ); document.write( "\n" ); document.write( "x = sqrt(-7), x = -sqrt(-7), or x = -4\r
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\n" ); document.write( "\n" ); document.write( "x = i*sqrt(7), x = -i*sqrt(7), or x = -4\r
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\n" ); document.write( "\n" ); document.write( "The actual roots are x = i*sqrt(7), x = -i*sqrt(7), or x = -4\r
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\n" ); document.write( "\n" ); document.write( "The first two are complex or imaginary roots. The third root is real and rational.\r
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\n" ); document.write( "\n" ); document.write( "The only actual rational root is x = -4\r
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