document.write( "Question 701566: Solve by substitution:
\n" ); document.write( "Y=3x-12
\n" ); document.write( "6x+4y=15
\n" ); document.write( "

Algebra.Com's Answer #432465 by mouk(232)\"\" \"About 
You can put this solution on YOUR website!
We have:
\n" ); document.write( "\"+6x%2B4y=15+\" and \"+y=3x-12+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So:
\n" ); document.write( "\"+6x%2B4%283x-12%29=15+\"
\n" ); document.write( "\"+6x%2B12x-48=15+\"
\n" ); document.write( "\"+18x=63+\"
\n" ); document.write( "\"+x=3.5+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "But \"+y=3x-12+\" so:
\n" ); document.write( "\"+y=3%283.5%29-12+\"
\n" ); document.write( "\"+y=-1.5+\"
\n" ); document.write( "
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