document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=701489>Question 701489</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you solve log of 54 base 3 and log of 48 base 4 without a calculator? I know if you have log of 9 base 3, to can turn 9 into 3^2 and the answer is 2.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #432442 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=432442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  How would you solve log of 54 base 3 and log of 48 base 4 without a calculator? <BR>\n" );
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document.write( "log3(54) = log3[27*2] = log3(27)+log3(2) = 3+log3(2)<BR>\n" );
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document.write( "log4(48) = log4(16*3) = log4(16)+log4(3) = 2+log4(3)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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