document.write( "Question 701380: John left school for home going 10km/h on his bike. Steve left 20 minutes later going 20km/h in order to catch up to John. How long did it take fore Steve to catch up to John \n" ); document.write( "
Algebra.Com's Answer #432415 by sachi(548)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "let after t min john starts Steve catch up John \n" ); document.write( "in t min \n" ); document.write( "John travels the distance =(10/60)*t km \n" ); document.write( "& Steve travels the distance =(20/60)*(t-20)km \n" ); document.write( "as they meet the distance traveled by both are same \n" ); document.write( "so (10/60)*t km=(20/60)*(t-20)km \n" ); document.write( "or t=2(t-20)=2t-40 \n" ); document.write( "or 2t-t=40 \n" ); document.write( "ot t=40 min \n" ); document.write( "so after 40 min of John starts Or 20 min of Steve starts they meet each other \n" ); document.write( " |