document.write( "Question 701380: John left school for home going 10km/h on his bike. Steve left 20 minutes later going 20km/h in order to catch up to John. How long did it take fore Steve to catch up to John \n" ); document.write( "
Algebra.Com's Answer #432415 by sachi(548)\"\" \"About 
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\n" ); document.write( "let after t min john starts Steve catch up John
\n" ); document.write( "in t min
\n" ); document.write( "John travels the distance =(10/60)*t km
\n" ); document.write( "& Steve travels the distance =(20/60)*(t-20)km
\n" ); document.write( "as they meet the distance traveled by both are same
\n" ); document.write( "so (10/60)*t km=(20/60)*(t-20)km
\n" ); document.write( "or t=2(t-20)=2t-40
\n" ); document.write( "or 2t-t=40
\n" ); document.write( "ot t=40 min
\n" ); document.write( "so after 40 min of John starts Or 20 min of Steve starts they meet each other
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