document.write( "Question 701427: the sum of four consecutive integers is 2 more than five times the first integer. \n" ); document.write( "
Algebra.Com's Answer #432413 by shanehhhh47(5)\"\" \"About 
You can put this solution on YOUR website!
First represent your values:
\n" ); document.write( "let x be the 1st integer
\n" ); document.write( "x+1 be the 2nd integer
\n" ); document.write( "x+2 be the 3rd integer
\n" ); document.write( "x+4 be the 4th integer
\n" ); document.write( "Then equate according to the given conditions:
\n" ); document.write( "x+x+1+x+2+x+3+x+4=2+5x
\n" ); document.write( "Combine Similar terms:
\n" ); document.write( "4x+6=2+5x
\n" ); document.write( "x=4
\n" ); document.write( "Therefore the integers are 4,5,6 and 7. :)
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