document.write( "Question 701427: the sum of four consecutive integers is 2 more than five times the first integer. \n" ); document.write( "
Algebra.Com's Answer #432413 by shanehhhh47(5)![]() ![]() You can put this solution on YOUR website! First represent your values: \n" ); document.write( "let x be the 1st integer \n" ); document.write( "x+1 be the 2nd integer \n" ); document.write( "x+2 be the 3rd integer \n" ); document.write( "x+4 be the 4th integer \n" ); document.write( "Then equate according to the given conditions: \n" ); document.write( "x+x+1+x+2+x+3+x+4=2+5x \n" ); document.write( "Combine Similar terms: \n" ); document.write( "4x+6=2+5x \n" ); document.write( "x=4 \n" ); document.write( "Therefore the integers are 4,5,6 and 7. :) \n" ); document.write( " |