document.write( "Question 62496: One type of gasohol is 10% alcohol and another type is 35% alcohol. How much of each type must be mixed to obtain 400 gallons of a 25% alcohol mixture? \n" ); document.write( "
Algebra.Com's Answer #43239 by josmiceli(19441)\"\" \"About 
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a = gasohol 10% alcohol
\n" ); document.write( "b = gasohol 35% alcohol
\n" ); document.write( "\".1a+%2B+.35b+=+.25%2A400\"
\n" ); document.write( "\"a+%2B+b+=+400\"
\n" ); document.write( "multiply 2nd equation by .1
\n" ); document.write( "\".1a+%2B+.1b+=+40\"
\n" ); document.write( "subtract 2nd from 1st
\n" ); document.write( "\".25b+=+60\"
\n" ); document.write( "\"b+=+240\"
\n" ); document.write( "\"a+%2B+b+=+400\"
\n" ); document.write( "\"a+%2B+240+=+400\"
\n" ); document.write( "\"a+=+160\"
\n" ); document.write( "240 gal of the .1 mixture and
\n" ); document.write( "160 gal of the .35 misture
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