document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62496>Question 62496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One type of gasohol is 10% alcohol and another type is 35% alcohol. How much of each type must be mixed to obtain 400 gallons of a 25% alcohol mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43238 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 400*.25=.10X+.35(400-X)<BR>\n" );
document.write( "100=.10X+140-.35X<BR>\n" );
document.write( ".25X=40<BR>\n" );
document.write( "X=40/.25<BR>\n" );
document.write( "X=160 GALLONS OF 10 % GASOHOL<BR>\n" );
document.write( "400-160=240 GALLONS OF 35 % ALCOHOL<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "400*.25=.10*160+.35*240<BR>\n" );
document.write( "100=16+84<BR>\n" );
document.write( "100=100<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );