document.write( "Question 701328: Show that the triangle with vertices (-5,2), (-2,5), and (5,-2) is a right angle. THANKS \n" ); document.write( "
Algebra.Com's Answer #432367 by MathLover1(20850)\"\" \"About 
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first find the equation of the line passing through (\"-5\",\"2\") and (\"-2\",\"5\")\r
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Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-5, 2) and (x2, y2) = (-2, 5).
\n" ); document.write( " Slope a is \"a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%285-2%29%2F%28-2--5%29+=+1\".
\n" ); document.write( " Intercept is found from equation \"a%2Ax%5B1%5D%2Bb+=+y%5B1%5D\", or \"1%2A-5+%2Bb+=+7\". From that,
\n" ); document.write( " intercept b is \"b=y%5B1%5D-a%2Ax%5B1%5D\", or \"b=2-1%2A-5+=+7\".
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\n" ); document.write( " y=(1)x + (7)
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\n" ); document.write( " Your graph:
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\n" ); document.write( "\n" ); document.write( "than find the equation of the line passing through (\"-5\",\"2\") and (\"5\",\"-2\")\r
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Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-5, 2) and (x2, y2) = (5, -2).
\n" ); document.write( " Slope a is \"a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%28-2-2%29%2F%285--5%29+=+-0.4\".
\n" ); document.write( " Intercept is found from equation \"a%2Ax%5B1%5D%2Bb+=+y%5B1%5D\", or \"-0.4%2A-5+%2Bb+=+0\". From that,
\n" ); document.write( " intercept b is \"b=y%5B1%5D-a%2Ax%5B1%5D\", or \"b=2--0.4%2A-5+=+0\".
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\n" ); document.write( " y=(-0.4)x + (0)
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\n" ); document.write( " Your graph:
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\n" ); document.write( "\n" ); document.write( "than find the equation of the line passing through (\"-2\",\"5\") and (\"5\",\"-2\")\r
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Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-2, 5) and (x2, y2) = (5, -2).
\n" ); document.write( " Slope a is \"a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%28-2-5%29%2F%285--2%29+=+-1\".
\n" ); document.write( " Intercept is found from equation \"a%2Ax%5B1%5D%2Bb+=+y%5B1%5D\", or \"-1%2A-2+%2Bb+=+3\". From that,
\n" ); document.write( " intercept b is \"b=y%5B1%5D-a%2Ax%5B1%5D\", or \"b=5--1%2A-2+=+3\".
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\n" ); document.write( " y=(-1)x + (3)
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\n" ); document.write( " Your graph:
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\n" ); document.write( "\n" ); document.write( "now graph all three lines together:\r
\n" ); document.write( "\n" ); document.write( "\"y=x+%2B7\".........a slope is \"m=1\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-0.4x+\".........a slope is \"m%5B1%5D=-0.41\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-x+%2B+3\".........a slope is \"m%5B2%5D=-1\" which is negative reciprocal of \"m=1\"; \"m%5B2%5D=-1%2Fm=-1%2F1=-1\"...so, the line \"y=x+%2B7\" and \"y=-x+%2B+3\" are perpendicular to each other\r
\n" ); document.write( "\n" ); document.write( "if two of lines perpendicular to each other, and three intersecting line form a triangle, triangle is a right angle triangle
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