document.write( "Question 701202: I really need help. I am doing something terribly wrong and I do not know how to do this. \r
\n" ); document.write( "\n" ); document.write( "x^2+4x-12=0\r
\n" ); document.write( "\n" ); document.write( "Thank you very much!
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Algebra.Com's Answer #432313 by Simnepi(216)\"\" \"About 
You can put this solution on YOUR website!
to solve quadratic equations the first thing is to look for factor pairs of the constant term, in this case that is -12.
\n" ); document.write( "factors of -12 are: (remember one of these has to be a negative number because negative multiplied by positive gives a negative answer)
\n" ); document.write( "plus/minus 1 and 12:
\n" ); document.write( "plus/minus 2 and 6:
\n" ); document.write( "plus/minus 3 and 4.
\n" ); document.write( "Now we look to see if any of those factor pairs can be added to make the coefficient of the x term (that's the number in front of the x) which is +4.
\n" ); document.write( "Obviously the factor pair we need are plus/minus 2 and 6 because -2 + 6 = +4
\n" ); document.write( "Now we get two brackets and put an x in both and one of the factors in the other
\n" ); document.write( "Like this
\n" ); document.write( "(x+6)(x-2)
\n" ); document.write( "making this equal zero means that either one of these brackets could equal zero, that is
\n" ); document.write( "either (x+6)=0 OR (x-2)=0
\n" ); document.write( "If x+6=0 then x=-6
\n" ); document.write( "Or If x-2=0 then x=2
\n" ); document.write( "We do not know which of these solutions is the correct one so we give them both.
\n" ); document.write( "That is
\n" ); document.write( "x=-6 or x=2
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