document.write( "Question 701202: I really need help. I am doing something terribly wrong and I do not know how to do this. \r
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document.write( "x^2+4x-12=0\r
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document.write( "Thank you very much!
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Algebra.Com's Answer #432313 by Simnepi(216)![]() ![]() You can put this solution on YOUR website! to solve quadratic equations the first thing is to look for factor pairs of the constant term, in this case that is -12. \n" ); document.write( "factors of -12 are: (remember one of these has to be a negative number because negative multiplied by positive gives a negative answer) \n" ); document.write( "plus/minus 1 and 12: \n" ); document.write( "plus/minus 2 and 6: \n" ); document.write( "plus/minus 3 and 4. \n" ); document.write( "Now we look to see if any of those factor pairs can be added to make the coefficient of the x term (that's the number in front of the x) which is +4. \n" ); document.write( "Obviously the factor pair we need are plus/minus 2 and 6 because -2 + 6 = +4 \n" ); document.write( "Now we get two brackets and put an x in both and one of the factors in the other \n" ); document.write( "Like this \n" ); document.write( "(x+6)(x-2) \n" ); document.write( "making this equal zero means that either one of these brackets could equal zero, that is \n" ); document.write( "either (x+6)=0 OR (x-2)=0 \n" ); document.write( "If x+6=0 then x=-6 \n" ); document.write( "Or If x-2=0 then x=2 \n" ); document.write( "We do not know which of these solutions is the correct one so we give them both. \n" ); document.write( "That is \n" ); document.write( "x=-6 or x=2 \n" ); document.write( " |