document.write( "Question 701195: What is the answer to sqrt5x^2-3x=2x \n" ); document.write( "
Algebra.Com's Answer #432306 by Simnepi(216)\"\" \"About 
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Hopefully your question is \"sqrt%285x%5E2-3x%29=2x\"
\n" ); document.write( "To solve this we need to square both sides to get rid of that nasty square root on the left hand side.
\n" ); document.write( "this will give \"5x%5E2-3x=4x%5E2\"
\n" ); document.write( "rearranging this equation and simplifying we get
\n" ); document.write( "\"x%5E2-3x=0\"
\n" ); document.write( "we can take out the common factor of x to give
\n" ); document.write( "x(x-3)=0
\n" ); document.write( "therefore x=0 or x-3=0 i.e. x=3
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