document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=701054>Question 701054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "The denominator of a fraction exceeds twice the numerator by 3. If the numerator is increased by 4 and the denominator is decreased by 3, the resulting fraction is 5 over 6. Find the original fraction. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #432303 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=432303\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X/(2X+3)<BR>\n" );
document.write( "(X+4)/(2X+3-3)=5/6<BR>\n" );
document.write( "(X+4)/(2X)=5/6 CROSS MULTIPLY<BR>\n" );
document.write( "5*2X=6(X+4)<BR>\n" );
document.write( "10X=6X+24<BR>\n" );
document.write( "10X-6X=24<BR>\n" );
document.write( "4X=24<BR>\n" );
document.write( "X=24/4<BR>\n" );
document.write( "X=6 <BR>\n" );
document.write( "2*6+3=15<BR>\n" );
document.write( "6/15 IS THE ORIGINAL FRACTION.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "(6+4)/(15-3)=5/6<BR>\n" );
document.write( "10/12=5/6<BR>\n" );
document.write( "5/6=5/6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );