document.write( "Question 701084: A truck can be rented from Basic Rental for $50 per day plus $0.20 per mile. Roadrunners charges $20 per day plus $0.50 per mile to rent the same truck. How many miles must be driven in a day to make the rental cost for Basic Rental a better deal than that for Roadrunners?
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Algebra.Com's Answer #432301 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! 50+.20x<20+.50x \n" ); document.write( ".20x-.50x<20-50 \n" ); document.write( "-.30x<-30 \n" ); document.write( "x>-30/-.30 not the change in the < sign. It changes to a > sign \n" ); document.write( "when dividing by a negative value. \n" ); document.write( "x>100 miles makes Basic Rental a better deal. \n" ); document.write( "Proof: \n" ); document.write( "Let the mileage be 101 miles. \n" ); document.write( "50+.20*101<20+.50*101 \n" ); document.write( "50+20.20<20+50.50 \n" ); document.write( "70.20<70.50 \n" ); document.write( " |