document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62484>Question 62484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve 3x(to the 3rd)+7x(squared)-22x-8=0,  given that negative one third is a solution.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43226 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve 3x(to the 3rd)+7x(squared)-22x-8=0, given that negative one third is a solution. <BR>\n" );
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document.write( "3x^3+7x^2-22x-8=0 and x=-1/3 is a zero<BR>\n" );
document.write( "If x=-1/3 is a zero:<BR>\n" );
document.write( "x-1/3=0<BR>\n" );
document.write( "3x-1 is a factor.<BR>\n" );
document.write( "Divide the polynomial by 3x-1 to get:<BR>\n" );
document.write( "3x^2+6x-24<BR>\n" );
document.write( "Using the quadratic formula you get:<BR>\n" );
document.write( "x=[-6+-sqrt(36-4*3*-24]/-6<BR>\n" );
document.write( "x=[-6+-18]/(-6)<BR>\n" );
document.write( "x=-2 or x=4<BR>\n" );
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document.write( "Final Soluition:<BR>\n" );
document.write( "x=-1/3, x=-2, x=4<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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