document.write( "Question 701153: my dad was 10 years old twice the age of me 5 years ago. 5 years later he would be twice the age f me. find current ages \n" ); document.write( "
Algebra.Com's Answer #432243 by CRandunu(8)\"\" \"About 
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let the present ages of father and me be f and m\r
\n" ); document.write( "\n" ); document.write( "f-5=2*(m-5)+10
\n" ); document.write( "f-5=2m----------(1)\r
\n" ); document.write( "\n" ); document.write( "f+5= 2(m+5)
\n" ); document.write( "f+5=2m+10
\n" ); document.write( "f-5=2m ---------(2)\r
\n" ); document.write( "\n" ); document.write( "these two equations are identical :-)\r
\n" ); document.write( "\n" ); document.write( "hence we come to a conclusion anyhow my age should be a positive integer which should be greater than 5 ,because given before 5 years ago I exist and not my age is zero!!\r
\n" ); document.write( "\n" ); document.write( "it gives m>5 where m=6 or 7 or 8 or....or n and
\n" ); document.write( "from (1) m=(f-5)/2 >0 where m=(f-5)/2 = 6 or 7 or 8 or....or n ------(A) \r
\n" ); document.write( "\n" ); document.write( "According to this to get a positive m>5 integer for my age \"m\" , father's present age can be 17 or 19 or 21 or 23 or 23 or 25 or 27 or 29 or 31 or 33 or 35 or....(2n+5)etc (substitute these ages in (A) and see)\r
\n" ); document.write( "\n" ); document.write( "hence there's a group of answers
\n" ); document.write( "when m=6 ,f= 17
\n" ); document.write( "when m=7, f=19
\n" ); document.write( "when m=8, f=21
\n" ); document.write( ".............
\n" ); document.write( ".............
\n" ); document.write( "when m=n-1 ,f= 2n+3
\n" ); document.write( "when m=n , f=2n+5 where n>5 and a integer
\n" ); document.write( "etc
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